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openzeppelin-contracts/test/helpers/math.js

34 lines
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// Array of number or bigint
const max = (...values) => values.slice(1).reduce((x, y) => (x > y ? x : y), values.at(0));
const min = (...values) => values.slice(1).reduce((x, y) => (x < y ? x : y), values.at(0));
const sum = (...values) => values.slice(1).reduce((x, y) => x + y, values.at(0));
// Computes modexp without BigInt overflow for large numbers
function modExp(b, e, m) {
let result = 1n;
// If e is a power of two, modexp can be calculated as:
// for (let result = b, i = 0; i < log2(e); i++) result = modexp(result, 2, m)
//
// Given any natural number can be written in terms of powers of 2 (i.e. binary)
// then modexp can be calculated for any e, by multiplying b**i for all i where
// binary(e)[i] is 1 (i.e. a power of two).
for (let base = b % m; e > 0n; base = base ** 2n % m) {
// Least significant bit is 1
if (e % 2n == 1n) {
result = (result * base) % m;
}
e /= 2n; // Binary pop
}
return result;
}
module.exports = {
min,
max,
sum,
modExp,
};