Get peers returns now both in and outbound peers

pull/150/head
obscuren 11 years ago
parent dfa38b3f91
commit da66eddfcc
  1. 16
      ethereum.go
  2. 4
      peer.go

@ -144,6 +144,18 @@ func (s *Ethereum) InboundPeers() []*Peer {
return inboundPeers[:length]
}
func (s *Ethereum) InOutPeers() []*Peer {
// Create a new peer slice with at least the length of the total peers
inboundPeers := make([]*Peer, s.peers.Len())
length := 0
eachPeer(s.peers, func(p *Peer, e *list.Element) {
inboundPeers[length] = p
length++
})
return inboundPeers[:length]
}
func (s *Ethereum) Broadcast(msgType ethwire.MsgType, data interface{}) {
msg := ethwire.NewMessage(msgType, data)
eachPeer(s.peers, func(p *Peer, e *list.Element) {
@ -151,6 +163,10 @@ func (s *Ethereum) Broadcast(msgType ethwire.MsgType, data interface{}) {
})
}
func (s *Ethereum) Peers() *list.List {
return s.peers
}
func (s *Ethereum) ReapDeadPeers() {
for {
eachPeer(s.peers, func(p *Peer, e *list.Element) {

@ -335,9 +335,9 @@ func (p *Peer) pushHandshake() error {
// Pushes the list of outbound peers to the client when requested
func (p *Peer) pushPeers() {
outPeers := make([]interface{}, len(p.ethereum.OutboundPeers()))
outPeers := make([]interface{}, len(p.ethereum.InOutPeers()))
// Serialise each peer
for i, peer := range p.ethereum.OutboundPeers() {
for i, peer := range p.ethereum.InOutPeers() {
outPeers[i] = peer.RlpData()
}

Loading…
Cancel
Save