Return `url` of new post on publish

pull/464/head
Matt Baer 4 years ago
parent 73e0b72878
commit b010484493
  1. 4
      posts.go
  2. 1
      read.go

@ -125,6 +125,7 @@ type (
Views int64 `json:"views"`
Owner *PublicUser `json:"-"`
IsOwner bool `json:"-"`
URL string `json:"url,omitempty"`
Collection *CollectionObj `json:"collection,omitempty"`
}
@ -612,6 +613,7 @@ func newPost(app *App, w http.ResponseWriter, r *http.Request) error {
newPost.extractData()
newPost.OwnerName = username
newPost.URL = newPost.CanonicalURL(app.cfg.App.Host)
// Write success now
response := impart.WriteSuccess(w, newPost, http.StatusCreated)
@ -1124,7 +1126,7 @@ func (p *Post) processPost() PublicPost {
func (p *PublicPost) CanonicalURL(hostName string) string {
if p.Collection == nil || p.Collection.Alias == "" {
return hostName + "/" + p.ID
return hostName + "/" + p.ID + ".md"
}
return p.Collection.CanonicalURL() + p.Slug.String
}

@ -315,7 +315,6 @@ func viewLocalTimelineFeed(app *App, w http.ResponseWriter, req *http.Request) e
author = p.Collection.Title
} else {
author = "Anonymous"
permalink += ".md"
}
i := &Item{
Id: app.cfg.App.Host + "/read/a/" + p.ID,

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